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文件名称:2024-2025学年第二学期初中毕业班适应性训.pdf
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2024-2025学年第二学期初中毕业班适应性训练

数学参考答案

一、选择题:本题共10小题,每小题4分,共40分。

1.D2.A3.C4.D5.B6.B7.B8.C9.A10.D

二、填空题:本题共6小题,每小题4分,共24分。

1

11.π12.30013.14.x-215.816.18

3

三、解答题:本题共9小题,共86分。

分解:解不等式①得<2·································································分

17.(8)x2

解不等式②得x??2·········································································4分

所以不等式组的解集是-2≤x<2·······················································6分

所以它的整数解是-2,-1,0,1·······················································8分

18.(8分)解:?AD∥BC,

??ADB?EBC·······························································2分

在△ADB和△EBC中,

??A?BEC

?

?ADBE

??ADB?EBC

?

?△ADB≌△EBC···························································5分

∴=··········································································6分

∴+=···································································7分

∵AD=BE

∴+=··································································8分

2

2a?1a?1

19.(8分)先化简,再求值:(?1)?,其中a2?1.

aa

2

2a?1a?1

解:(?1)?

aa

2a?1a(a?1)(a?1)

=(?)?·······································································2分

aaa

1