郑州市2025年中招第二次适应性测试
数学评分参考
一、选择题(每小题3分，共30分)
题号12345678910
答案ACDBBDBCBC
二、填空题(每小题3分，共15分)
题号1112131415
2
答案?1（答案不唯一）变多m4??222?
2
三、解答题(本大题共8个小题，满分75分)
2
16.（1）原式6??32?2?1··································································4分
2
1····························································································5分
（2）原式2
(a?2b)?b(4a?b)
222
a?4ab?4b?4ab?b·························································4分
22
a?5b·················································································5分
17.（9分）（1）从平均数和中位数角度来看，甲种草莓的单果质量大于乙种草莓的单果质量，
但甲种草莓的糖度低于乙种草莓的糖度；从方差角度来看，甲种草莓单果质量的方差和糖度
的方差均大于乙种草莓，说明甲种草莓的单果质量不均匀，糖度的大小波动比较大.由于人
们对草莓口感的要求会比较高，所以我建议推广乙种草莓.（合理即可）···················6分
（2）由于乙种草莓的单果质量比较小，所以技术人员需要运用种植技术提高草莓的单果质
量.··············································································································9分
18.9分（1）2，6·······················································································2分
（）
（2）或·················································································5分
?2?x?0x?2
（3）
如图，过点作⊥轴，垂足为，
AADxD
过点作⊥，垂足为，
BBEDAE
∴∠ODA∠E.
∵OABC为正方形，
∴OAAB，∠OAB90°.
∴∠∠，∠∠，
DAO+EAB90°